Question

IN THE GIVEN FIGURE AB IS THE DIAMETER OF THE CIRCLE ABE IS AN ISOCELES TRIANGLE WITH AE=BE IF BAD=75 DEGREE THEN WHAT IS THE MEASURE OF DBE

Answer 1

Answer:

angleADB=90°. [ angle subtended by the diameter]

In triangle ABD

angleABD+angleADB+angleDAB=180°. [ angle sum property]

angleABD=15°

In triangleBEA

angleBEA=90°. [ angle subtended by the diameter]

BE =AE. [given]

angleEAB=angleEBA. [angles opposite to equal sides]

angleBEA+2angleEBA=180°. [ angle sum property]

2angleEBA=90°

angleEBA=45°

angleDBE=angleEBA+angleABD

therefore

angleDBE=60°

Hope it helps