Question

in the given figure,AB is the diameter of the circle and CD||AB. If ∠DAB = 25°, calculate
(i) ∠ACD and (ii) ∠CAD​

Answer 1

Answer:

In ΔADB

we know that angle mathe on semicircle

90° so

∠ADB=90°

& CD∣∣AB'

∠CDA=∠DAB=25°

∠CDA=90+25=115

and ABCD is cyclic so

∠CAB+∠CDB=180°

∠CAD+∠DAB+115=180

∠CAD=180−115−25

∠CAD=40°

Step-by-step explanation:

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Answer 2

Answer:

hi here is ur answer

Step-by-step explanation:

In the given figure AB is a diameter of the circle and CD ∥ AB. If ∠DAB = 250

Calculate ∠ACD and ∠CAD