Question

In the given figure, AB is the tangent of the circle with centre O. If ∠DOA = 130°, then find the angle ∠DAB.

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

DAB + BCD = 180˚ [Oppo. Angles of a cyclic quadrilateral]

DAB + 130˚ = 180˚

DAB = 180˚ – 130˚

DAB = 50˚

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