In the given figure, AB is the tangent of the circle with centre O. If ∠DOA = 130°, then find the angle ∠DAB.
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Step-by-step explanation:
DAB + BCD = 180˚ [Oppo. Angles of a cyclic quadrilateral]
DAB + 130˚ = 180˚
DAB = 180˚ – 130˚
DAB = 50˚
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