Question

In the given figure AB is trisected at D and F and DE||GF||BC if BC=6 cm , then FG equals

Answer 1

Answer:

$\huge\underline\mathfrak\color{Red}solution..$

TO PROVE : AF : FC = ?

CONSTRUCTION: DG // BF

PROOF : In triangle ADG,

AE = ED ( given)

EF // DG ( by construction)

So AF = FG……. ………(1) (a line passing through the mid point of any side of a triangle, parallel to the other side, bisects the third side)

Now in triangle CBF

BD = DC ( given)

DG // BF ( by construction)

So, FG = GC ( Same reason) ……..(2)

Now, by (1) & (2)

AF = FG = GC

=> AF : FC = 1:2

$\huge\underline\mathfrak\color{blue}hence..proved..$

$\huge\underline\mathfrak\color{Red}follow..me$