Question

In the given figure, AB ll CD, find the value of x and y.​

Answer 1

Answer:

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Step-by-step explanation:

GivenAB∥CD&RQisthetransversalthen

∠QHC=∠AFH=115

o

{Correspondingangles}

Nowy+∠AFH=180

o

{Linearpair}

⇒y=180

o

−115

o

⇒y=65

o

NowAB∥CD&PQisthetransversalthen

∠PBF=x{Correspondingangles}

Sox=85

o

Answer 2

$\huge \bf{QUESTION}$

$\huge \sf \bf{answer}$

Given AB∥CD & RQ is the transversal then

∠QHC=∠AFH=115°

{Corresponding angles}

Now y+∠AFH=180°

{Linearpair}

⇒y=180 °

−115

⇒y=65 °

Now AB∥CD & PQ is the transversal then

∠PBF=x{Correspondingangles}

So x=85 °