Question

in the given figure ab ll cd ll ef.if angle cef =160° and angle bce = 10°.then find angle x​

Answer 1

Given

AB||CD||EF

∠CEF = 160°

∠BCE = 10°

To Find

Value of x

Solution

∵ EF||CD

∴ ∠CEF + ∠ECD = 180° [Co. int angles]

⇒ 160° + ∠ECD = 180°

⇒ ∠ECD = 180° - 160° = 20°

Now,

∵ AB||CD

∴ ∠ABC = ∠BCD [alt. angles]

⇒ ∠ABC = ∠BCE + ∠ECD

⇒ x = 10° + 20° = 30°

Answer 2

Step-by-step explanation:

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