In the given figure, AB llCD and EF ll GH . find the values of x,y,z and t.
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SOLUTION:-
AB || CD and EF || GH
•°• PQ || RS
•°• x = 60° ..........{vertically opposite angle}
now,
EF || GH
•°• PR || QS
∠PRQ = ∠SQR ......{Alternate angle}
x = y
•°• y = 60°
now,
∠APR = ∠PQS .......{corresponding angle}
∠PQS = 110°
∠PQS + ∠BQS = 180° ....{ straight line}
110° + z = 180°
z = 180 - 110
z = 70°
now,
∠BQS = ∠RSQ ......{corresponding angle}
z = t
t = 70°
The values of x, y, z and t is 60°, 60°, 70° and 70°
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