Question

In the given figure, AB parallel CD, AG parallel
EF and BD = FG. Prove that
EBF CONGRUENT CDG​

Answer 1

Answer:

Step-by-step explanation:

AB=CB      eq.1

AB=CD     eq.2

from eq.1 and 2 we know that AB=CB=CD

therefore ABCD is a square.

EF bisects BD at G.

therefore EG=FG

consider triangle FGB and EGD.

EG=FG

angleDEG= angleGFB (alternate interior angles)(AB is parallel to CD)

angleDGE=angleBGF (vertically opposite angles)

therefore by ASA congruency both triangles are congruent

BG=DG (cpct)

hence proved

Answer 2

Answer:

ans is vbskakjahKw

Step-by-step explanation:

498cdbbwa