in the given figure ab parallel CD find the value of angle pqr
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The answer is 95°.
If we draw a ll line XY through middle of the ∠pqr
Then , AB II XY and PQ is a transversal.
∠BPQ =∠XQP =40°[alt. int ∠s]
Similarly , CD II XY and QR is a transversal.
∠DRQ =∠ XQR =55°
∠XQP+ ∠XQR= ∠PQR
40° + 55° =95°
I hope it is helpful..
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