in the given figure ab parallel CD prove that angle BAE minus angle DCE is equals to angle AEC
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Where's the figure? Please insert it.
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Answer:
I hope this resolves your query.
Step-by-step explanation:
Is it true figure of the question?
Solution:
Given: AB//CD.
To prove: <BAE - <DCE = <AEC
Construction: draw a line EF//AB//CD
Proof: AB//CD//EF.
<AEF + <AEC = <FEC
<FEA + <BAE = 180 ( co-interior angle)...eq`n (1).
and <FEC + <DCE = 180 (co-interior angle).
<FEA + <AEC + <DCE = 180 ......eq`n (2).
Now, comparing eq`n (1) and eq`n (2), we get;
<FEA + < BAE = <FEA + <AEC +<DCE.
< BAE = < AEC + <DCE...[ <FEA replaced ].
<BAE - <DCE = <AEC.
Hence, the required condition be proved.
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