Question

in the given figure AB parallel to CD,angle APQ=60degree

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Answer 1

Answer:

The value of x and y is 60 degree and77 degree

Given,

In figure, AB∥CD , degree∠APQ=60 degree and degree∠PRD=137 degree

From figure,

RR is a point angle.

So, degree∠R=180 degree

⇒∠QRP+∠PRD=180

⇒∠QRP=180−137

⇒∠QRP=43

In △PQR ,

x+y+43=180

⇒x+y=180−43

⇒x+y=137 __1

∵ AB∥CD , ∠APQ and ∠PQR alternate angles.

So, ∠APQ=∠PQR

⇒x=60 degree

Plug the value in equation-1,

⇒60+y=137

⇒y=137−60

∴ y=77 degree

So, The value of x and y is 60 degree and 77 degree