in the given figure AB||PQ Find the value of x and y
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X= 70 ° and Y=50°
25°+Y=75° ( corresponding angles )
Y= 50°
Now BEF + QFE = 180° (CO INTERIOR ANGLES)
BEF + 75° =180°
BEF= 105°
BEF= 20 + GEF
GEF= 105° -20°
GEF= 85°
NOW GEF +X+GEF = 180° ( ANGLE SUM OF TRIANGLE)
X= 180- 110
X = 70°
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