in the given figure AB1=B1B2=B2B3=B3C.if B2A2PARALLEL TO CB,then find the ratio in which A2 divides LINE segment AB.
Answers
Given : B1, B2, B3,. and A1,A2, A3,. . have been marked at equal distances
To Find : C divides AB in what ratio
Solution:
in Δ B₅CB & Δ A₈CA
∠B₅CB = ∠ A₈CA( vertically opposite angles)
∠CBB₅ = ∠CAA₈ ( alternate angles)
∠CB₅B = ∠CA₈A ( alternate angles)
Δ B₅CB ≈ Δ A₈CA (AAA)
Similar triangles corresponding angles are congruent and the corresponding sides are proportional
=> BC/AC = BB₅ /AA₈
B1, B2, B3,. and A1,A2, A3,. . have been marked at equal distances
=>BB₅ = 5x
AA₈ = 8x
BC/AC = 5x / 8x
=> BC/AC = 5/8
=> AC/BC = 8/5
C divided AB in 8 : 5 ratio
Learn More:
To divide a line segment AB in the ratio 3:4, we draw a ray AX, so ...
brainly.in/question/13663596
The ratio in which the y axis divides the line segment joining the ...
brainly.in/question/20223782
To divide a line segment BC internally in the ratio 3 : 5, we draw a ...
brainly.in/question/25266911