In the given figure, ∠ABC =65°, ∠BCE = 30°, ∠DCE = 35°and ∠CEF =145°.Prove that AB II EF.
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∠ABC=65°
∠BCD= 30°+30°=65°
because alternative angles are equal
therefore,AB || CD ---(i)
∠FEC+∠DCE= 108°
Therefore CD||EF ---(ii)
Using (i) and (ii)
AB||EF
hence proved
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