Question

in the given figure, /ABC-90°,AB-6cm,BC-8cm seg BD is the median Find BD

Please share step by step explanation thank you :)​

Answer 1

Answer:

10

Step-by-step explanation:

by Pythagoras theorem in right and triangle

AC'2=AB'2+BC'2

=6'2+8'2

ROOT AC = 100

AC= 10

THEN TAKE TWO TRIANGLE ANGLE

Answer 2

Concept:

A triangle is said to be right-angled if one of its inner angles is 90 degrees, or if any one of its angles is a right angle. The right triangle or 90-degree triangle is another name for this triangle. In trigonometry, the right triangle is crucial.

In a right-angled triangle, the square of the hypotenuse side is equal to the sum of the squares of the other two sides, according to Pythagoras's Theorem. These triangle's three sides are known as the Perpendicular, Base, and Hypotenuse. Due to its position opposite the 90° angle, the hypotenuse in this case is the longest side. When the positive integer sides of a right triangle (let's say sides a, b, and c) are squared, the result is an equation known as a Pythagorean triple.

Given:

In the given figure it is given that:

$AB=6cm\\BC=8cm\\\\AD=DC$

$BD$ is the median on $AC$.

To find

Find the value of $BD$.

Solution:

it is given that:

$AB=6cm\\BC=8cm\\\\AD=DC$

$BD$ is the median on $AC$.

Apply Pythagoras's Theorem in Δ$ABC$.

$AB^{2}+BC^{2}=AC^{2} \\6^{2}+8^{2} =AC^{2}\\36+64=AC^{2}\\100=AC^{2}\\\sqrt{100}=AC^{2}\\ AC=10$

Now, It is known that:

$BD=\frac{1}{2}AC$

$BD=\frac{1}{2}*10$

      $=5cm$

Hence, the value of $BD=5cm$.

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