In the given figure, Δ ABC and Δ ABD are such that
AD = BC, ∠1 = ∠2 and ∠3 = ∠4. Prove that BD = AC.
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Answer:
In △ABD and △BAC,
AD=BC (Given)
∠DAB=∠CBA (Given)
AB=BA (Common)
∴△ABD≅△BAC (By SAS congruence rule)
∴BD=AC (By CPCT)
And, ∠ABD=∠BAC (By CPCT)
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