in the given figure ABC and DBC are two isosceles triangle on the same base BC if BTC is 120 degree ab d 40 degree find BAC and ADC
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Step-by-step explanation:
∆ ABC and ∆ DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see figure ). If AD is extended to interest BC at P, show that (i) ∆ ABD = ∆ ACD
Answer Solve
Given:
∆ABC is isosceles,
AB = AC
..(1) Also, DBC is isosceles,
DB = DC
..To prove: A ABD = ∆ ACD.
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