In the given figure, ABC and DBC are two triangles on the same base BC and AD intersects BC at O. If AO = 4cm and DO = 9 cm then the ratio of areas of triangles ABC and DBC is
1 point
Captionless Image
2 : 3
4: 9
8: 27
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Step-by-step explanation:
The given figure can be re-drawn as shown in the above figure where AE and DF are heights of Δ ABC and Δ BCD respectively.
Now ΔAOE and ΔFOD are similar.
As ∠EOA=∠FOD [Opposite angle], ∠AEeO=∠DFO [right-angles] and ∠EaO=∠FdO [AE∥FD and AD interested
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