Question

In the given figure, ∠ABC = ∠DCB = 90° AB = 6, DC = 8 then find A(∆ABC)/A(∆DCB)
Please answer this question. This is of my today's exam paper.

Answer 1

Answer:

6/8

Step-by-step explanation:

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given that:-

<ABC = 90°

so the area of triangle

= 1/2(base × perpendicular height

=> area of ∆ABC = 1/2(AB × BC)

=> 1/2(6 × BC)

similarly,

<DCB = 90°

area of ∆DCB= 1/2(8 × BC)

NOW,

(area of∆ABC) / (area of ∆DCB) = [1/2(6 × BC) / 1/2(8 × BC)]

=> (6×BC)/(8×BC)

=> 6/8

Answer 2

Answer:

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