In the given figure, ABC is a
right-angled triangle with B= 90°)
AB = 48 cm and BC = 14 cm. With AC as
diameter a semicircle is drawn and with
BC as radius, a quadrant of a circle is
drawn. Find the area of the shaded region.
Answers
Answered by
1
Answer:
In triangle ABC , right angled at B,
AC^2=AB^2+BC^2
(phythagoras therom)
28^2+21^2
784+441 = 1225
AC=35cm
Area of shaded region = Area of triangleABC + Area of semi circle with diameter AC - area of quadrant with radius BC
1/2(21*28)+1/2*22/7*35/2*35/2
- -1/4*22/7*21*21
- =294+481.25-346.5
- 775.25-346.5
- =428.75 cm ^2
Answered by
0
Answer:
1164.142 cm²
Step-by-step explanation:
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