Question

in the given figure ABC is a right triangle right angled at a. Find the area of a shaded region. if AB= 16cm BC= 20cm and O is the center of the incircle of triangle Abc​

Answer 1

Step-by-step explanation:

AC=√20^2-16^2=12cm

join o to vertices of triangle

1/2(20+16+12)*r=1/2*16*12

48*r=16*12

r=4

area of circle=3.14*16=50.24cm2

area of shaded portion=1/2*16*12-50.24

=96-50.24=45.76cm2