Question

In the given figure, ABC is a triangle in which
AB = AC and D is a point on AB. Through D, a
line DE is drawn parallel to BC and meeting
AC at E. Prove that AD = AE.​

Answer 1

Step-by-step explanation:

Given:ABC is a triangle in which

AB = AC and D is a point on AB. Through D, a

AB = AC and D is a point on AB. Through D, aline DE is drawn parallel to BC and meeting

AB = AC and D is a point on AB. Through D, aline DE is drawn parallel to BC and meetingAC at E.

To Prove:AD = AE.

CONSTRUCTION: To construct a line to make DE perpendicular to AF

SOLUTION: IN triangle AFD and AFE

ADF = AEF

AFD = AFE

AF = AF

Triangle ADF congruent to AEF (by ASA congruency)

AD=AE (BY CPCT)

Answer 2

Answer:

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