In the given figure, ABC is a triangle in which AB - AC. If
D is a poin on BC produced Prove that AD > AC.
Answers
Answered by
2
Answer:
Given, D is a point on side BC such that AB=AC.
AD > AC
In ∆ABC,
∠ACD = ∠B + ∠BAC
∠ACB + ∠BAC [ Since, AB = AC so, ∠C = ∠B]
∠CAD + ∠CDA +∠BAC [ Since, ∠ACB =
∠CAD + ∠CDA]
∴∠ACD > ∠CDA
∴AD > AC
Step-by-step explanation:
Similar questions