Question

in the given figure ABC is a triangle PQ parallel BC and QR is the angle bisector of angle PQC if RC=10 then find QC?


plz slove...​

Answer 1

Answer:

angle pqr=angle rqc 1

also,

angle pqr=angle qrc ( alternate angle). 2

from 1 and 2

angle rqc = angle qrc

by theorem,

RC=qc

as rc is 10

therefore. qc is also 10

Answer 2

Given,

$PQ||BC$

$QR$ is the angle bisector of $\angle PQC$

$RC=10units$

To Find,

Value of $QC$

Solution

We can simply solve this mathematical problem by using the mathematical process.

We know,

$PQ||BC$

By Property of Alternate angles,

$\angle PQR = \angle QRC$       (Equation 1)

$QR$ is the angle bisector of $\angle PQC$,

$\angle PQR = \angle RQC$       (Equation 2)

From equations (1) and (2),

$\angle RQC = \angle QRC$

Hence, $\triangle CRQ$ is an isosceles triangle.

$QC= RC$

$RC=10units$

$QC=10units$

Hence, the value of the $QC$ is $10 units$