Question

in the given figure, ABC is a triangle with LEDB = ZACB. Prove that
AABC AEBD. IT BE = 6 cm, EC = 4 cm, BD = 5 cm and area of
ABED = 9 cm", calculate:
Length of AB.
(i) Area of AABC.​

Answer 1

1. solution : In A ABC and A EBD, ZACB = ZEDB (given) ZABC = ZEBD (common) ZABC - ZEBD (by AA- similarity). 1) We have (AB) / (BE) = (BC) / (BD) => AB = (6 xx 10) / 5 =% 3D 12 cm 2) "Area of A ABC" / "Area of A BED" = `((AB) / (BE)) ^ 2 => Area of A ABC = '(12/6) ^ 2 xx 9 cm = 4 xx 9 cm ^ 2 = 36 cm ^ 2