In the given figure ∆ABC is an isosceles triangle with AB = AC.
ABC = 35.Find
Question 3
BDC and BEC. answer fast
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Z ABC =35
therefore , Z BDC =35. ( angles in the same segment)
points A,B,E , C all lie in the circumference of the circle ,
therefore , ABEC is a cyclic quadrilateral
we know that Z ABC =35
ZABC + ZBEC = 180
( by solving )
Z BEC = 180-35
Z BEC = 145
hope it helps you!
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