in the given figure,ABC is an isosceles triangle with AB is equal to AC and angle BAD
is equal to 28 degree
find angle DAC
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Given : ABC is an isosceles triangle with AB is equal to AC
angle BAD equal to 28°
To find : angle DAC
Solution:
ΔABD and ΔACD
AB = AC
AD = AD common
∠ADB = ∠ADC = 90°
=> ΔABD ≅ ΔACD
=> ∠BAD = ∠DAC
∠BAD = 28°
=> ∠DAC = 28°
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