in the given figure abc is an wquolatersl triangle the coordinates of vertices b and c are 3,0 and -3,0 respectively find the coordinates of vertex a .
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Answer:
A = ( 0 , 3√3)
Step-by-step explanation:
abc is an Equilaietral Triangle so All sides should be equal
AB = BC = AC
BC = √(3 - (-3))² +(0-0)² = 6
=> AB = AC = 6
=> 6 = √(x-3)² + (y-0)² = √(x -(-3))² + (y-0)²
Squaring both sides
=> 36 = (x-3)² + y² = (x+3)² + y²
Comparing alst two
=> x² + 9 -6x = x² + 9 + 6x
=> -12x = 0
=> x = 0
putting x = 0
=> 36 = 3² + y²
=> y² = 27
=> y = ±3√3
But as per picture shiwn y looks in +ve axis
so A = ( 0 , 3√3)
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Step-by-step explanation : . ............
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