Question

in the given figure,∆ABC is right angle at A.D is a mid-point of BC find the area of ∆ABC if AC= 12cm and AD= 6.5cm​

Answer 1

Answer:

Since mid-point of the hypotenuse of a right triangle is equidistant from the vertices.

∴CA=CB=OC⇒CA=CB=6.5 cm⇒AB=13 cm

In right triangle OAB, we have

AB

2

=OB

2

+OA

2

⇒13

2

=OB

2

+12

2

⇒OB=5

∴ar(△AOB)=

2

1

(OA×OB)=

2

1

(12×15)=30 cm

2

Answer 2

Answer:

30cm^2

Step-by-step explanation:

if AD= 6.5

so BC= 13

AC = 12

ab=

13^2=12^2*ab^2

169-144= ab^2

✓25= ab

ab = 5

area of ∆abc

1/2*5*12=30cm^2