Question

In the given figure △ABC is right angled at A. AD is drawn perpendicular to BC. Prove that ∠BAD=∠ACB

Answer 1

Answer:

Ex 6.5,3 In figure, ABD is a triangle right angled at A and AC ⊥ BD. Show that AB2 = BC . ... From theorem 6.7, If a perpendicular is drawn from the vertex of the right angle to.

Answer 2

Answer:

Hence proved

Step-by-step explanation:

Since ∠BAD = x° and ∠ACB = z°

and we got x = z (from the fig.)

Therefore, ∠BAD = ∠ACB