in the given figure ABC is right angled at B and BD is drawn perpendicular to AC. show that 1=2
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in triangle ABC and CDB,
angle A is common to both(SAY X),
angle ABC = angle ADB=90°
therefore angle ABD (1)= angle DCB(2) =180-90-x
=90-x
Hence angle ABD (1)= angle DCB(2)
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