Question

in the given figure∆ABC is right angled at B .if AC = 20 cm and tanA=5/2, find the value of (cos²Ø + sec²Ø)​

Answer 1

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• ${cos}^{2} = \frac{x}{5}$
• ${sec}^{2} = \frac{5}{x}$
• x = 10/3
• Cos ^2 + sec^2 = 2/3+ 3/2
• = 13/6