Question

IN THE GIVEN FIGURE, ABC IS TRIANGLE AND BD IS A MEDIAN. THEN WE HAVE, (a) AB + BC + CA = 2BD (b) AB + BC + CA = 2BD (c) AB + BC + CA <BD (d) NONE PF THESE



give me the solution also​

Answer 1

The sum of measures of any two sides of the triangle is greater than the third side.

So, In triangle ABM

AB+BM>AM ..................... (1)

In triangle AMC

MC+AC>AM ...................... (2)

Add (1) and (2),

AB+(BM+MC)+AC>AM+AM 

AB+BC+AC>2AM