in the given figure ABC is triangle. if AD= 3.6cm , AB=10cm, AE=1.8cm, Then the length of AC to make DEllBC is
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Answer:
AC=33.8cm
Step-by-step explanation:
AD=3.6cm,AB=10cm,AE=1.8cm,
AB-AD=10-3.6=6.4cm,BD=6.4cm
AD/BD=AE/EC
3.6*10/6.4*10=1.8*10/EC
36/64=18/EC
9/16=18/EC (CROSS-MULTIPLICATION)
9*EC=16*18
9*EC=288
EC=288/9
EC=32
AC=AE+EC
=1.8+32
=33.8cm
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