In the given figure, ABC is triangle in which AB = AC. X and Y are points on AB
and AC such that AX =AY. Prove that BY = CX.
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Step-by-step explanation:
In ΔAYB and ΔAXC
AX=AY (given)
∠ACX=∠ACY (AX=AY)
∠BAC=∠BAC (common)
so, ΔAYB≅ΔAXC (by ASA congruene)
now,
CX=BY (cpct)
hence proved
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