Question

in the given figure ABCandDCBar right-angled at A and D respectively and AC=DB.
prove that ∆ABC=∆DCB​

Answer 1

Answer:

Given:-

_________

Angle A = angle D = 90°

AC = DB

To prove :-

_________

∆ ABC ~ ∆ DCB

Proof :-

_________

In ∆ ABC and ∆ DCB ,

AC = DB...........(Given)

BC= BC............( Common side)

Angle CAB = angle BDC = 90°

Therefore,∆ ABC ~∆ DCB........(From the RHS congruence property)

Hope it will help you...✌️