in the given figure ABCD find the value of x
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angle CBA =180°-80° (Linear pair)
angle BAD= 180°-70° (Linear pair)
angle DCB=180°-70°(Linear pair)
angle CDA =180°-x (Linear pair)
In quadrilateral ABCD , By angle sum property of quadrilateral
angle CBA+angle BAD+angle DCB+angle CDA=360°
180°-80° + 180°-70° +180°-70° + 180°-x= 360°
720°- 360°= 80° + 70°+ 70° + x
360° = 220° + x
360° - 220 ° = x
140° = x
Step-by-step explanation:
You can also do it by using this property :
Sum of external angles of a quadrilateral is 360°
But I gave detailed explanation simply by angle sum property of the quadrilateral.
Hope it helps:)
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