Question

In the given figure ABCD IS A CYCLIC quadrilateral & angle ACB=90 , then find the value of X.​

Answer 1

angle ADC+angleCBA=180 [Property of cyclic quadrilateral]

angle 120+angleCBA=180

AngleCBA=180-120=60degree

NOW , In traingleABC

angleACB+angleCBA+angleCAB=180

90+60+x=180

x=180-(90+60)

x=180-150

=30 ans

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Answer 2

Answer:

ABCD is a cyclic quadrilateral. we have  

∠ABC+∠ADC=180  

 

∠ABC=180    −120  

=60  

 

Also  ∠ACB=90  ( angle on a semi circle )  

In ΔABC we have  

∠BAC+∠ACB+∠ABC=180

  ∠BAC+90 +60  =180

 ∠BAC=180   −150  =30  

Step-by-step explanation:

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