in the given figure ABCD is a cyclic quadrilateral. find the value of x and y
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We know that,
the sum of the opposite angles of cyclic quadrilateral is supplementary, means 180°.
so, angleA + angleC = 180°
4y+20-4x=180
4y-4x=160......(I)
angleB + angleD = 180°
3y-5-7x+5=180°
3y-7x=180.......(ii)
Multiply eqn(I) by 3 and eqn(ii) by 4
we get,
12y-12x=480
12y-28x=720
By elimination method,
16x=-240
x=-15
now put the value of x in eqn (I)
4y-4(-15)=160
4y+60=160
4y=100
y=25
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