in the given figure ABCD is a cyclic quadrilateral if angle BCD is equal to 110 and angle ABD = 60 degree find the measure of angle D A and angle ADB
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ABCD is a cyclic quadrilateral
In cyclic quadrilateral opposite angles are supplementary .
∠ BCD + ∠ DAB = 180° , SO
110° + ∠ DAB = 180°
∠ DAB = 70°
From angle sum property of triangle , we get in triangle ABD.
∠ ABD + ∠ DAB + ∠ ADB= 180°
= 60° + 70°
= 130°
∠ ADB= 180° - 130°
∠ ADB= 50°
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BEST OF LUCK
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FRIEND...
THANKYOU YOU ASKING QUESTION
-------------------------------------------------------
HERE YOUR ANSWER
-------------------------------------------------------
ABCD is a cyclic quadrilateral
In cyclic quadrilateral opposite angles are supplementary .
∠ BCD + ∠ DAB = 180° , SO
110° + ∠ DAB = 180°
∠ DAB = 70°
From angle sum property of triangle , we get in triangle ABD.
∠ ABD + ∠ DAB + ∠ ADB= 180°
= 60° + 70°
= 130°
∠ ADB= 180° - 130°
∠ ADB= 50°
THANKYOU
BEST OF LUCK
CHEERS
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