Question

In the given figure, ABCD is a cyclic quadrilateral in which AE is drawn parallel to CD and 2
BA is produced to F. IF ZABC=70° and ZFAE=30°, find ZBCD.
C300
B70°
11am
m
O and R are point on sides MN and ON respectively. If ar 2​

Answer 1

Answer:

angle BCD = 140

Step-by-step explanation:

angle B + angle CDA = 180 (opp. angles of a cyclic quad are supplementary)

70 + angle D =180

angle CDA =110

But angle EAD = angle CDA ( Alt int angles with CD||AE with the transveral AD)

angle CDA =110

angle BCD = angle FAD ( ext angle = int angle)

But, angle FAD = angle FAE + angle AED

∵ angle BCD =  angle FAE + angle AED

∵ angle BCD = 30 + 110

∵ angle BCD = 140