Question

in the given figure , ABCD is a cyclic quadrilateral In which AB||CD and ∠B=65°, then find other angles​

Answer 1

Answer:

A=65°

D=115°

C=115°

Step-by-step explanation:

Since ABCD is cyclic quad. it's opposite angles sum should be 180°. So D= 180-65=115. (eq-1 )

Now, we have AB || CD so by co-interior angle property sum of A and D should be 180°. So A= 65°.

Similarly from eq-1 we have got C= 115°.

Answer 2

Answer:

Angle A=65

angle C=angle D=115

Step-by-step explanation:

In cyclic quadrilateral

If AB//CD it will be trapisium

so, angle A=angle B

angle A=65

angle C=angle D

angle C+angleD=360_(65+65)

2×angle C=230

angle C=230÷2=115

angle C=115

angleD=115