in the given figure ABCD is a cyclic quadrilateral in which AB is parallel to DC if angle BAD = 100 then find angle ADC
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angle ADC 80°
Step-by-step explanation:
∠BAD+∠BCD=180° (opposite angles of a cyclic quadrilateral are supplementary).
∴100°+∠BCD=180°
∠BCD=80°
(ii) ∠ADC=∠BCD (Alt angles are equal)
∠ADC=80°
(iii) ∠ABC=∠BAD (Alt angles are equal)
∠ABC=100°
because the opposite side of a cyclic quadrilateral are supplementary.
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