Question

In the given figure, ABCD is a cyclic quadrilateral. O is the centre of the circle. If DCE = 55°, find the value of angle BOD(x).
please help me by doing step by step.​

Answer 1

Given <dce=55,<DCB=125andreflex<BOD=2×125=250

therefore,<BOC=110

Answer 2

Answer:

angleBCD=180-55 (linear pair)

angleBCD=125 degree

Now as ABCD is a cyclic quadrilateral, angleBCD+angleBAD=180

Therefore angleBAD=55degree

angleBOD=2(angleBAD)

Therefore angleBOD =110 degree

Step-by-step explanation:

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