in the given figure ABCD is a cyclic quadrilateral the diagonal AC and BD are joined
if angle ACB is equal to 30 degree and angle BAC is equal to 35 degree find angle abc
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∠ABC = 115°
Step-by-step explanation:
In the given figure,
Given,
∠BDC = 35° and ∠ACB = 30°
∠ADB =∠ACB (Angle in the same segment are always equal)
⇒∠ADB = 30°
Now,∠ADC = ∠ADB + ∠BDC
= 30° + 35°
= 65°
Also,∠ADC + ∠ABC = 180° (Opposite angles of a quadrilateral are always equal)
65° + ∠ABC = 180°
∠ABC = 180°- 65°
∠ABC = 115°
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