In the given figure ABCD is a cyclic quadrilateral with side AB as a diameter of the circle (2) If ∠ADC = 125°, then find the measure of the following angles, giving reasons
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Answer:
Given:
ABCD is a cyclic quadrilateral with AB as the diameter of the circle.
Also, ∠ADC=140
We have to find: ∠BAC.
Then,
∠ADC+∠ABC=180
....(since the sum of the opposite angles of a quadrilateral is 180
∴∠ABC=180 −140 =40
Also, ∠ACB=90
....(since the angle subtended by a diameter at the circumference of the circle, is 90
∴ In ΔABC we have,
∠ACB=90 and ∠ABC=40
So, ∠CAB=180 −(∠ACB+∠ABC)=180 −(90 +40 )
∴∠BAC=50
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