Question

In the given figure, ABCD is a gm. E
is any point on AB. CB and DE are
produced to meet at F. Prove that
(i) ar (∆CEF) = ar (∆BDF)
(ii) if AE = EB,
then ar (∆BCE) = ar (∆BDE)
=1/4
ar (||gm ABCD)​

Answer 1

Answer:

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