Math, asked by sukhneet6, 5 months ago

In the given figure, ABCD is a Il gm, prove that
AABC = ACDA.​

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Answered by h3rm515
2

Step-by-step explanation:

in ∆ABC and ∆CDA,

AB = CD (Opposite side of a parallelogram are equal)

BC = DA (Opposite sides of a parallelogram are equal)

AC = CA (Common)

Therefore, ∆ABC is congruent to ∆CDA

Angle ABC = Angle CDA (By CPCT)

Hence Proved.

Answered by ydharmendra991
0

Answer:

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