In the given figure, ABCD is a Il gm, prove that
AABC = ACDA.
Attachments:
Answers
Answered by
2
Step-by-step explanation:
in ∆ABC and ∆CDA,
AB = CD (Opposite side of a parallelogram are equal)
BC = DA (Opposite sides of a parallelogram are equal)
AC = CA (Common)
Therefore, ∆ABC is congruent to ∆CDA
Angle ABC = Angle CDA (By CPCT)
Hence Proved.
Answered by
0
Answer:
follow me and like my answers mark me as a brainlist please don't forget it ohkk dear friends..
Attachments:
Similar questions