Question

In the given figure, ABCD is a kite with
AC and BD as diagonals and ABC =
30°. Find the value of x



​

Answer 1

Answer:

blue of x = 75

blue of x = 75 angle cob=90

blue of x = 75 angle cob=90angle obc=1/2 of 30= 15

blue of x = 75 angle cob=90angle obc=1/2 of 30= 15so 90+15+x=180

blue of x = 75 angle cob=90angle obc=1/2 of 30= 15so 90+15+x=180105+x=180

blue of x = 75 angle cob=90angle obc=1/2 of 30= 15so 90+15+x=180105+x=180x=180-105

blue of x = 75 angle cob=90angle obc=1/2 of 30= 15so 90+15+x=180105+x=180x=180-105x=75

Answer 2

Answer:

75°

Step-by-step explanation:

The diagonals of a kite are perpendicular to each other and bisect the angles.

=> Angle BOC = 90°

Angle ABC = 30°

=> Angle CBO = 30°/2 = 15°

According to Angle Sum Property of Triangle, the sum of three angles of a triangle is 180°.

In triangle OBC,

90°+15°+x = 180°

=> 105°+x = 180°

=> x = 180°-105°

=> x = 75°