Question

In the given figure ABCD is a parallelogram.AE And BE are angle bisector of /_A and /_B respectively
show that /_AEB=90°

Answer 1

Answer:

Step-by-step explanation:

let each bisected angle be x

angle A = 2x

Similarly let y be each of the bisected angle

2y = angle B

2x+2y = 180 deg ( adjacent angles of a parallelogram)

x+y = 90

In triangle ABE

x +y + angle AEB = 180 deg. ( sum of angles of a triangle)

90+angle AEB = 180 deg

angle AEB = 180-90

Angle AEB = 90 deg

Answer 2

Answer:

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